Find three points that lie on the circle calculator

This calculator will find either the equation of the circle from the given parameters or the center, radius, diameter, circumference (perimeter), area, eccentricity, linear eccentricity, x-intercepts, y-intercepts, domain, and range of the entered circle. Also, it will graph the circle. Steps are available.

Related calculators: Parabola Calculator, Ellipse Calculator, Hyperbola Calculator, Conic Section Calculator

Your Input

Find the center, radius, diameter, circumference, area, eccentricity, linear eccentricity, x-intercepts, y-intercepts, domain, and range of the circle $$$x^{2} + y^{2} = 9$$$.

Solution

The standard form of the equation of a circle is $$$\left(x - h\right)^{2} + \left(y - k\right)^{2} = r^{2}$$$, where $$$\left(h, k\right)$$$ is the center of the circle and $$$r$$$ is the radius.

Our circle in this form is $$$\left(x - 0\right)^{2} + \left(y - 0\right)^{2} = 3^{2}$$$.

Thus, $$$h = 0$$$, $$$k = 0$$$, $$$r = 3$$$.

The standard form is $$$x^{2} + y^{2} = 9$$$.

The general form can be found by moving everything to the left side and expanding (if needed): $$$x^{2} + y^{2} - 9 = 0$$$.

Center: $$$\left(0, 0\right)$$$.

Radius: $$$r = 3$$$.

Diameter: $$$d = 2 r = 6$$$.

Circumference: $$$C = 2 \pi r = 6 \pi$$$.

Area: $$$A = \pi r^{2} = 9 \pi$$$.

Both eccentricity and linear eccentricity of a circle equal $$$0$$$.

The x-intercepts can be found by setting $$$y = 0$$$ in the equation and solving for $$$x$$$ (for steps, see intercepts calculator).

x-intercepts: $$$\left(-3, 0\right)$$$, $$$\left(3, 0\right)$$$

The y-intercepts can be found by setting $$$x = 0$$$ in the equation and solving for $$$y$$$: (for steps, see intercepts calculator).

y-intercepts: $$$\left(0, -3\right)$$$, $$$\left(0, 3\right)$$$

The domain is $$$\left[h - r, h + r\right] = \left[-3, 3\right]$$$.

The range is $$$\left[k - r, k + r\right] = \left[-3, 3\right]$$$.

Answer

Standard form: $$$x^{2} + y^{2} = 9$$$A.

General form: $$$x^{2} + y^{2} - 9 = 0$$$A.

Graph: see the graphing calculator.

Center: $$$\left(0, 0\right)$$$A.

Radius: $$$3$$$A.

Diameter: $$$6$$$A.

Circumference: $$$6 \pi\approx 18.849555921538759$$$A.

Area: $$$9 \pi\approx 28.274333882308139$$$A.

Eccentricity: $$$0$$$A.

Linear eccentricity: $$$0$$$A.

x-intercepts: $$$\left(-3, 0\right)$$$, $$$\left(3, 0\right)$$$A.

y-intercepts: $$$\left(0, -3\right)$$$, $$$\left(0, 3\right)$$$A.

Domain: $$$\left[-3, 3\right]$$$A.

Range: $$$\left[-3, 3\right]$$$A.

Equation of a Circle Calculator is a free online tool that displays the equation of a circle of a given input. BYJU’S online equation of a circle calculator tool makes the calculation faster, and it displays the equation in a fraction of seconds.

How to Use the Equation of a Circle Calculator?

The procedure to use the equation of a circle calculator is as follows:
Step 1: Enter the circle centre and radius in the respective input field
Step 2: Now click the button “Find Equation of Circle” to get the equation
Step 3: Finally, the equation of a circle of a given input will be displayed in the new window

What is the Equation of a Circle?

In geometry, a circle is a two-dimensional round shaped figure where all the points on the surface of the circle are equidistant from the centre point (c). The distance from the centre of the circle to the surface is called the radius (R). The equation of a circle can be calculated if the centre and the radius are known. Thus the equation of a circle is given by
(x-h)2 +(y-k)2 = r2
Where
(h, k) – centre coordinates
r – radius

How do you find the points that lie on a circle?

To determine the position of a given point with respect to a circle, all we need to do is to find the distance between the point and the center of the circle, and compare it with the circle's radius. If the distance is greater than the radius, the point lies outside.

How do you find the radius of a circle with 3 points?

Equation of circle in general form is x² + y² + 2gx + 2fy + c = 0 and in radius form is (x – h)² + (y -k)² = r², where (h, k) is the centre of the circle and r is the radius. The equation of the circle is x2 + y2 = 1.

Can a circle pass through any 3 points?

Case 1: A circle passing through 3 points: Points are collinear. Consider three points, P, Q and R, which are collinear. If three points are collinear, any one of the points either lie outside the circle or inside it. Therefore, a circle passing through 3 points, where the points are collinear, is not possible.

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