The general equation of a straight line can be written as y = mx + c where m is the slope and c is the y-intercept. Show
Answer: The equation of a line passing through the points (2, 3) and (4, 6) is 3x - 2y = 0Let us proceed step by step to find the equation of the line. Explanation: Let us consider the given points (2, 3) and (4, 6). As we know that the equation of a line passing through the points (x1, y1) and (x2, y2) is given by y - y1 = m (x - x1). Here, m is the slope given by the formula m = (y2 - y1) / (x2 - x1) Try using Cuemath's Slope Calculator that helps you to calculate the slope in a few seconds. Hence on substituting the given points in the equation of a line, we get y - 3 = m (x - 2) m = (y2 - y1) / (x2 - x1) m = (6 - 3) / (4 - 2) m = 3 / 2 Substituting value of m in y - 3 = m (x - 2), we get ⇒ y - 3 = 3 / 2 ( x - 2 ) ⇒ 2y - 6 = 3x - 6 ⇒ 2y - 3x = 0 ⇒ 3x - 2y = 0 You can use Cuemath's online Equation of Line calculator to find the equation of line. Therefore, the equation of a line passing through the points (2, 3) and (4, 6) is 3x - 2y = 0
How do you find the equation of a line that passes through points?How to Find the Equation of a Line from Two Points. Find the slope using the slope formula. ... . Use the slope and one of the points to solve for the y-intercept (b). ... . Once you know the value for m and the value for b, you can plug these into the slope-intercept form of a line (y = mx + b) to get the equation for the line.. What is the equation of line passing through two points?The two-point form of a line is used for finding the equation of a line given two points (x1,y1) ( x 1 , y 1 ) and (x2,y2) ( x 2 , y 2 ) on it. The two point-form of a line is:y−y1=y2−y1x2−x1(x−x1) y − y 1 = y 2 − y 1 x 2 − x 1 ( x − x 1 ) OR y−y2=y2−y1x2−x1(x−x2) y − y 2 = y 2 − y 1 x 2 − x 1 ( x − x 2 ) .
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